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2 years ago

James bought a cake that weighs 3 and 1 over 4 pounds. How many ounces does the cake weigh? Show your work. (5 points)

1 answer:

8 0

The weight of James cake in ounces is 52 ounces and the Pint of water dispensed in 20 seconds is 24 pints

<h3>Weight</h3>

Weight of cake = 3 1/4 pounds

1 pound = 16 ounces

Number of ounces the cake weigh = 3 1/4 pounds × 16 ounces

= 13/4 × 16

= (208) / 4

= 52 ounces

Water dispensed per second = 0.15 gallons
Number of seconds = 20 seconds

1 gallon = 4 quarts

0.15 gallon = 0.6 quarts

1 quart = 2 pints

0.6 quart = 1.2 pints

Pint of water dispensed in 20 seconds = 1.2 × 20

= 24 pints of water

Learn more about weight:

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Broccoli cost 1.50 per pound at a store. How much money does 32 ounce of broccoli cost.

spayn [35]

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$3.00

Step-by-step explanation:

Step 1. Calculate the <em>pounds of broccoli</em>.

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===============

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3 years ago

g On a certain daily flight, Air Northeast has a policy of booking as many as 22 people on an airplane that can seat only 19. Pa

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Answer:

55.82% probability that there will not be enough seats available for all booked passengers.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a booked passenger arriving is independent of other booked passengers. So we used the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The airline books 22 people on a flight

This means that $n = 22$

Past studies have revealed that only 89% of the booked passengers actually arrive for the flight.

This means that $p = 0.89$

Find the probability that there will not be enough seats available for all booked passengers.

The airplane seats 19, so this is the probability of more than 19 passengers arriving.

$P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 20) = C_{22,20}.(0.89)^{20}.(0.11)^{2} = 0.2718$

$P(X = 21) = C_{22,21}.(0.89)^{21}.(0.11)^{1} = 0.2094$

$P(X = 22) = C_{22,22}.(0.89)^{22}.(0.11)^{0} = 0.0770$

$P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22) = 0.2718 + 0.2094 + 0.0770 = 0.5582$

55.82% probability that there will not be enough seats available for all booked passengers.

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3 years ago