The dimensions of the crate that will minimize the total cost of material are 10, 10, and 29.
<h3>How to compute the dimension?</h3>
The volume will be:
= Length × Width × Height
= lwh
For the square base, w = l
2880 = w²h
The cost function will be:
C = 12wl + 4wh + 4lh
Put l = w.
C = 12w² + 8wh
C = 12w² + 8w(2880/w²)
C = 12w² + 23040/w
Differentiate with respect to w
C'(w) = 0
24w = 23040/w²
24w³ = 23040
w³ = 960
w = 10 approximately
The length is 16 as well as they are the same. The height will be:
= 2880/w²
= 2880/10²
= 28.8 = 29
Therefore, the dimensions are 10, 10, and 29.
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