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Allisa [31]
3 years ago
12

The reciprocal of 1/50 is _____. 0 1 50

Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

50

Step-by-step explanation:

hope dis helps :/

lara [203]3 years ago
6 0
50 is the reciprocal because you flip the fraction so 50/1

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-2 - 10j = -9j -3<br>Is that <br>no solution<br>one solution<br>infinitely many solution​
jasenka [17]
It's one solution.

no matter how you solve it, it will equal j = 1.
4 0
3 years ago
Is (6, 2) a solution to this system of equations? x + 4y = 14 2x + 4y = 20
uranmaximum [27]
No it’s not because (6,2) would be a no solution so no
3 0
3 years ago
A bag contains purple marbles and blue marbles, 41 in total. The number of purple marbles is 4 less than 2 times the number of b
Andreas93 [3]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

1) We have purple (p) and blue (b) marbles in a bag, and 41 marbles total so:

p+b = 41

2) we want to know how many purple marbles we have, so let's rearrange for p:

p = 41 - b

3) Our problem gives us an expression for the purple marbles in terms of the blue,  let's write it using math symbols instead of words:

<em>"The number of purple marbles is 4 less than 2 times the number of blue marbles."</em>

so: p = 2b - 4

3) Now we're going to plug this in (or substitute it) for our p in our first equation, and solve for b

p = 41 - b

2b - 4 = 41 - b     (substitution)

2b = 45 - b         ( add 4 to both sides)

3b = 45               (add b to both sides)

b = 15                  (divide both sides by 3)

4, last step!)

Now we know we have 15 blue marbles, that's great! But we still want to know how many purple marbles we have.

41- 15 = 26 purple marbles

4 0
3 years ago
Help please!!!!! ASAPPPP
r-ruslan [8.4K]

Answer:

the numerator is 31 and the bottom is 8

Step-by-step explanation:

5 0
2 years ago
Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
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