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xxTIMURxx [149]
3 years ago
9

There are chocolates in a box, all identically shaped. There are 8 filled with nuts, 16 with caramel, and 14 are solid chocolate

. You randomly select one piece, eat it, and then select a second piece. Find the probability of selecting 2 solid chocolates in a row.
Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

P = \frac{91}{703} ≅ 12.95%.

Step-by-step explanation:

The total amount of chocolates in the box is 8 + 16 + 14 = <u>38</u>, 14 of which are solid.

Let's calculate the probability of getting a solid chocolate in the first selection:

P(1S) = \frac{14}{38} = \frac{7}{19}.

Given that the first piece was solid, there are now 37 pieces of chocolate in the box, 13 of which are solid. Let's now calculate the probability of selecting another solid chocolate:

P(2S\,|\,1S) =  \frac{13}{37}.

Thus, the probability of selecting two solid chocolates in a row is the product of the two probabilities calculated above:

P = \frac{7}{19}\,.\,\frac{13}{37} = \frac{91}{703}.

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7 0
4 years ago
the perimeter of a rectangle is 50 inches the length l is twice the width w. what is the area of the rectangle?? ❗️show work❗️
mr Goodwill [35]
Hey. Let me help you on this one.

In order for us to solve this problem, we will need to set up an equation which we can solve later. I will also be attaching an image with the work shown in case you don't understand my explanation. Make sure to read over it since it will help you with your studies.

We know that the length is twice the width, meaning that a=2b, with "a" standing for length, and "b" standing for width. Now that we have formed an equation for length, we can actually form an equation for perimeter.

P=2(2b)+2b

Let's simplify the equation so it's easier and less confusing for us to solve it.

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Let's divide 6 from both sides, thus eliminating all variables except for b on the right side.

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4 0
4 years ago
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