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AVprozaik [17]
2 years ago
15

Solve y

Mathematics
1 answer:
Ksivusya [100]2 years ago
5 0

The value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

<h3>How to solve for y?</h3>

The equation is given as:

-3 = 7\left(y-\dfrac97\right)

Open the bracket

-3 = 7y - 9

Add 9 to both sides of the equation

7y = 6

Divide both sides by 7

y= 6/7

Hence, the value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

Read more about equations at:

brainly.com/question/2972832

#SPJ1

<u>Complete question</u>

Solve for y

-3 = 7\left(y-\dfrac97\right)

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icang [17]
27/10=2.7

Radians are the arc of circle divide by 10.

6 0
4 years ago
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How to do this question I am having a problem trying to do it
nika2105 [10]
Hey there :)

We need to use trigonometry here
Given is the angle   = 30°
And one side           = 26
With a missing side =  x

The missing side is the opposite of the given angle, we have the adjacent but we don't know the value of the hypotenuse, so we need to use Tangent

Tan α = \frac{opposite}{adjacent}
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5 0
3 years ago
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Please help me with this -2 - (-0.7)
Amanda [17]

Anytime you subtract a negative number, it changes it to adding a positive number.

-2 + 0.7

Since we are adding, we will have an arrow going to the right

-2 + 0.7 = -1.3

Therefore, we will have a point starting at -2, an arrow pointing to the right and stopping at -1.3

Best of Luck!

8 0
4 years ago
Find the distance between the points (–15, 3) and (–9, 8). Question 11 options: A) units B) units C) units D) units
AlladinOne [14]

Step-by-step explanation:

distance formula d=

√(X2 - X1)² + (Y2 - Y1)²

= √(-9-15)² + (8-3)²

=√(-24)² + (5)²

=√576 + 25

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4 0
3 years ago
xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc
leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ <u>28.6 km</u>

<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

4 0
3 years ago
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