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Romashka-Z-Leto [24]
4 years ago
8

Solve the equation 4+3(x+2)=-8 A) -6 B) 6 C) -2/3 D) 2/3

Mathematics
1 answer:
natulia [17]4 years ago
8 0
4+3(x+2)=-8
4+3x+6=-8
10+3x=-8
-10 -10
3x= -18
X= -6
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La probabilidad de que un dia cualquiera, carlos almuerce pollo frito es de 0,4. La probabilidad de que almuerce hambuergues es
MAXImum [283]

Answer:

0.6

Step-by-step explanation:

La fórmula para calcular la probabilidad de dos eventos se da como:

P (A⋃B) = P (A) + P (B) - P (A ⋂ B)

De la pregunta, sabemos que:

Probabilidad de que Carlos haya comido pollo frito: P (C) = 0.4.

Probabilidad de que Carlos coma una hamburguesa para el almuerzo: P (H) = 0.3.

Probabilidad de que Carlos almorce pollo frito y hamburguesa el mismo día: P (C ⋂ H) = 0.1.

Probabilidad de que Carlos coma pollo frito o hamburguesa para el almuerzo:

P (C ⋃ H) =?

Por lo tanto, aplicando nuestra fórmula:

P (C ⋃ H) = P (C) + P (H) - P (C ⋂ H)

P (C ⋃ H) = 0.4 + 0.3 - 0.1

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3 years ago
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Elden [556K]

Answer:

yx

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A 16\dfrac1216 2 1 ? kilometer stretch of road needs repairs. Workers can repair 2\dfrac142 4 1 ? kilometer of road per week. Ho
olganol [36]

Answer:

7\frac{1}{3} weeks.

Step-by-step explanation:    

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To find the number of weeks it will take to repair the stretch we will divide 16\frac{1}{2} by 2\frac{1}{4}

\text{Number of weeks it will take to repair the stretch of road}=16\frac{1}{2}\div 2\frac{1}{4}

Upon converting our mixed fractions into improper fractions we will get,

\text{Number of weeks it will take to repair the stretch of road}=\frac{33}{2}\div \frac{9}{4}

Dividing a fraction with another fraction is same as multiplying the 1st fraction with the reciprocal of second fraction.

\text{Number of weeks it will take to repair the stretch of road}=\frac{33}{2}\times \frac{4}{9}

\text{Number of weeks it will take to repair the stretch of road}=\frac{33*2}{9}

\text{Number of weeks it will take to repair the stretch of road}=\frac{11*2}{3}

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3 years ago
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