A,
lower stated limit of class123 to 125 = 123
upper stated limit of class123 to 125 = 125
b.
lower stated limit of class129 to 131 = 129
upper stated limit of class129 to 131 = 131
c,
lower real limit of class123 to 125 = 122.5
upper real limit of class123 to 125 = 125.5
d.
lower real limit of class129 to 131 = 128.5
upper real limit of class129 to 131 = 131.5
e. mid-point of class interval 120 to 122 is 121
f. Not sure
Well I don't know !
Let's get together and work it out.
You said that -2x - 3 = -4x + 3
Add 4x to each side: 2x - 3 = 3
Add 3 to each side: 2x = 6
Divide each side by 2 : x = 3 .
Hi,
Equation;
Variable n is given so no need to write it down. Instead use 8.
Solving:
Hope this helps.
r3t40
Answer:
31.6°
Step-by-step explanation:
<B = arctan (14.1/22.9) = 31.6°
Answer:
$1200
Step-by-step explanation:
There are 2 ways I immediately think about to solving the problem.
1) You multiply 30 and 200 , then multiply the product by .2 (i.e. 20%)
This way, you'll find out what the total amount was($6,000), then you multiply it by your commission rate.(.2 or 20%) to find your total profit($1,200).
2) You multiply 200 by .20 , then multiply the product by 30.
This way, you'll find out what your commission would be for a single item($40), then multiply by the total items sold (30) to find your total profit($1,200).
