Answer:
z = 86
Explanation:
90 - 68 = 12
180 - 78 = 102
102 + 12 = 114
180 - 114 = 86
Answer:
x = -21/5 = -4.200
Step-by-step explanation:
Answer:
and
are the locations higher than
foot
Step-by-step explanation:
We are given that Meg found one treasure at
foot
We are supposed to find Which of these location are higher than
foot?
i) 
So, this location is not higher than
foot
ii)
So, 
So, this location is higher than
foot
iii) - 1 foot

So,this location is not higher than
foot
iv)-2 feet
So,this location is not higher than
foot
v)
So, this location is higher than
foot
Answer:
V = 34,13*π cubic units
Step-by-step explanation: See Annex
We find the common points of the two curves, solving the system of equations:
y² = 2*x x = 2*y ⇒ y = x/2
(x/2)² = 2*x
x²/4 = 2*x
x = 2*4 x = 8 and y = 8/2 y = 4
Then point P ( 8 ; 4 )
The other point Q is Q ( 0; 0)
From these two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.
Now with the help of geogebra we have: In the annex segment ABCD is dy then
V = π *∫₀⁴ (R² - r² ) *dy = π *∫₀⁴ (2*y)² - (y²/2)² dy = π * ∫₀⁴ [(4y²) - y⁴/4 ] dy
V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴
V = π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )
V = π * [256/3 - 51,20]
V = 34,13*π cubic units
Answer:
0.025 grams
Step-by-step explanation:
The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:
Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)
Volume of drained water = 25 x 10⁻⁶ m³
Density of drained water = 1000 kg/m³
So, for the mass of drained water:
Density of drained water = Mass of drained water/Volume of drained water
Mass of drained water = (Density of drained water)(Volume of drained water)
Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)
<u>Mass of drained water = 0.025 gram</u>
Density