Write at least 5 arithmetic sequence and determine the common difference
2 answers:
An arithmetic sequence is a sequence where we use addition or subtraction to get to the next term.
Examples:
1, 3, 5, 7, 9...
Common Difference: Add 2
2, 6, 10, 14, 18, 22..
Common Difference: Add 4
100, 90, 80, 70, 60, 50..
Common Difference: Subtract 10.
25, 30, 35, 40, 45..
Common Difference: Add 5
1, 10, 19, 28, 37..
Common Difference: Add 9
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Answer:
the probability that their minimum is larger than 5 is 0.2373
Step-by-step explanation:
For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.
So the number of possibilities to select 5 numbers from 20 is:
<u>20 </u> * <u> 20 </u>* <u> 20 </u> *<u> 20 </u>* <u> 20 </u>
First number 2nd number 3rd number 4th number 5th number
Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are ways to select 5 numbers.
Then the number of possibilities in which their minimum number is larger than 5 is calculate as:
<u>15 </u> * <u> 15 </u>* <u> 15 </u> *<u> 15 </u>* <u> 15 </u>
First number 2nd number 3rd number 4th number 5th number
This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are
So the probability P can be calculate as:
Then the probability that their minimum is larger than 5 is 0.2373
Answer:
The solution for is all real numbers less that or equal to 36.
Step-by-step explanation:
Given expression:
To find the solution for
Solution:
In order to solve for , we will make sure to isolate the unknown variable
on left side alone by doing math operations on both sides of the inequality.
We have:
Multiplying both sides by 2.
The 2 on left side will cancel each other leaving alone.
Thus, we have:
Thus, solution for is all real numbers less that or equal to 36.