Answer:
2/10
Step-by-step explanation:
Probability of getting head on i'th coin = i/10
Probability Pr of getting head on 2nd coin (Event A) = 2 / 10
Probability Pr of getting head on 1st coin (Event B) = 1/10
Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;
where A∩B = Pr (A & B) = Pr A X Pr B
Putting in above formula :
Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u> / 1/10
= 2/10
The answer is the number will have to be less than 11 which means that it is a. 9
sorry if it is incorrect.
The answer in simplest form is 1/4.
F(x)=x^2 +8x
f(d-3) basically what we get from this is that the x value is d-3
to find f(d-3) simply plug in d-3 for every x
f(d-3)=(d-3)^2 + 8(d-3)
that would be one form of the answer, but we can also continue multiplying it out
f(d-3)= d^2-6d+9+8d-24
add like terms
f(d-3)=d^2+2d-15
have a nice day and i hope this helps :)
The first one is D. Y=-3+8x
The second one is G. -3/2x=y+2
