Multiply the amount of paint started with by the amount used:
2/3 x 1/2 = (2 x 1) / (3 x 2) = 2/6 = 1/3
There is 1/3 liter left
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
The answer is B there you go have a nice day
Answer:
True.
Step-by-step explanation:
Let's see the definition of in-center of a triangle.
The in-center of a triangle is a point located in the center of the triangle. It is equal distance from all sides of the triangle.
Therefore, it is True.
If we draw line segments from in-center to each vertex of the triangle, it will bisect the angles.
Herewith I have attached the figure for your reference.
Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />