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2 years ago

11

If y=-2 what is the solution for 4(x-3y)<6(x-3y)

1 answer:

Rzqust [24]2 years ago

5 0

Step 1) Plug in

<em>4(-2-3(-2)) < 6(-2-3(-2))</em>

Step 2) Take care of inner parentheses

<em>4(-2+6) < 6(-2+6)</em>

Step 3) Distribute

<em>-8+24 < -12+36</em>

Step 4) Add

16 < 24 (final answer)

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Please help I still do not understand these questions

solniwko [45]

Answer:

m = 2/5

Step-by-step explanation:

easy

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2 years ago

What is the volume of this triangular pyramid?

Vaselesa [24]

Answer:

1560 cubic inches

Step-by-step explanation:

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3 years ago

The point (4,-2) is the vertex of the graph of a quadratic function. The points (8,6) and (2,0) also fall on the graph of the fu

Elina [12.6K]

Answer:

Step-by-step explanation:

y = ax² + bx + c

~~~~~~~

(4, - 2), (8, 6), (2, 0)

a(4²) + b(4) + c = - 2

a(8²) + b(8) + c = 6

a(2²) + b(2) + c = 0

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64a + 8b + c = 6 ............... <em>(2)</em>

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Part C: (6, 0)

Part D: [ 4, ∞ )

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2 years ago

Gnoma [55]

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44

Step-by-step explanation:

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2 years ago

Read 2 more answers

find x if the distance between points L and M is 15 and point M is located in the first quadrant. L=(-6,2) M=(x,2)

aivan3 [116]

Answer:

Therefore,

$x = 9$

Step-by-step explanation:

Given:

Let,

point L( x₁ , y₁) ≡ ( -6 , 2)

point M( x₂ , y₂ )≡ (x , 2)

l(AB) = 15 units (distance between points L and M)

To Find:

x = ?

Solution:

Distance formula between Two points is given as

$l(LM)^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Substituting the values we get

$15^{2}=(x--6)^{2}+(2-2)^{2}\\\\225=(x+6)^{2}$

Square Rooting we get

$(x+6)=\pm \sqrt{225}=\pm 15\\\\x+6 = 15\ or\ x+6 = -15\\\\x= 9\ or\ x = -21$

As point M is located in the first quadrant

x coordinate and y coordinate are positive

So x = -21 DISCARDED

Hence,

$x = 9$

Therefore,

$x = 9$

3 0

3 years ago