You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²
At the same time, a truck moving speed o 8.50 m/s passes the car
D=v.t (for the truck)
And d= v.t+1/2.a.t²(for the car)
v.t=1/2.a.t²
t=2.v/a
t=2.8.50 m/s/ 2.70 m/s²
17m/2.70=6.29
This mean that the distance is
D=v.t=8.50m/s.6.29= 53.465 m/s
The speed of the car is
Vcar=a.t
2.7m/s2×× 53.65
=144.34
Answer:
The answer is 0.3 million per year
Step-by-step explanation:
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Answer:
It is 4/11
Step-by-step explanation:
Let x = 0.363636363636
Now as there are two digits repeating immediately after decimal point, we multiply above by 100 and get
100x = 36.363636363636
Now subtracting first equation from second we get
99x = 36
and hence
x = 36/ 99
= (9 × 4) / (9 × 11)
which then equals
= 4/11
Answer:
89°
Step-by-step explanation:
It is the first of a new study from the University of ÷|gsuj the most of the world the first time in a long time and money on what will happen in a way that would have to be careful about the future of this is to proa vide make be the it
