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3 years ago

Plz What is 0.04 is 1/10 of

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

8 0

If 0.04 is 1/10 of the answer, multiply 0.04 by 10 to find the answer:

0.04 x 10 = 0.4

netineya [11]3 years ago

7 0

0.04 is 1/10 of :

0.04 x 10 = 0,4

Ans = 0,4

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State the x value of the x intercept describe by the following linear equation: (-3x-2y = 9

aivan3 [116]

Answer:

x=-3

Step-by-step explanation:

-3x-2y=9

-3x-2(0)=9

-3x-0=9

-3x=9

x=-3

3 0

3 years ago

Solve for F ------- 2/3 + f = 1/5 A= 13/15 B= 7/15 C= - !3/15 D= - 7/15

nikdorinn [45]

$\\ \sf\longmapsto \dfrac{2}{3}+f=\dfrac{1}{5}$

$\\ \sf\longmapsto f=\dfrac{1}{5}-\dfrac{2}{3}$

$\\ \sf\longmapsto f=\dfrac{3-10}{15}$

$\\ \sf\longmapsto f=\dfrac{-7}{15}$

8 0

2 years ago

Read 2 more answers

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

3 0

3 years ago

Find the measures of the following angles

mezya [45]

Answer:

HGD: 117

FDG: 180

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Is 63 greater than 48.1 or less than PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)

timofeeve [1]

Answer:

63 is greater than 48.1 ...

63 > 48.1

Step-by-step explanation:

63 is greater than 48 remember. So you need to remove the [.1] and focus on the 63 and 48.

<h3>Hope it helps!!</h3><h3>Please mark me as the brainliest!!!</h3>

Thanks!!!!❤❣❤

5 0

3 years ago

Read 2 more answers