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max2010maxim [7]
3 years ago
5

The directrix of a parabola is y=−4y=−4 . The focus of the parabola is (−2,−2)(−2,−2) .

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0
Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).

Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²

Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3

Answer: y= \frac{1}{4} (x+2)^{2} - 3

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so.. C is the difference of all the three angles from 360 or  \bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148   whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture",  I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean?   well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from  360-x-2x-1-148

so... add them together then   and

\bf \begin{array}{cccclllll}
A&+&C&=&180\\
\uparrow &&\uparrow \\
(2x+1)&+&(360-x-2x-1-148)&=&180
\end{array}

solve for "x"


6 0
2 years ago
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3 years ago
Find the Equation of a line that has a slope of 5 and passes through ( 2, 8 ). Detailed answers would be appreciated.
Sophie [7]
Y = 5x+8<slope intercept 
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2 years ago
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Last Question<br> (You can ignore this sentence)
Harrizon [31]
3y-20+x+13=3x+9
3y-20+x+13+2y=180

3y-7+x=3x+9
3y=2x+16
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5y+x=187
5(2/3x+16/3)+x=187
10/3x+80/3+x=187
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5 0
2 years ago
7+2x/3=5 .............
borishaifa [10]

Answer:

x= -3

Step-by-step explanation:

7 + 2x/3 = 5

Subtract 7 from both sides,

2x/3 = 5-7

2x/3 = -2

Multiply by 3,

2x = -2*3

Divide by 2,

x = -2*3 / 2

x = -3

5 0
3 years ago
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