Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer:
225 in
Step-by-step explanation:
Answer:
<h2>5/16</h2>
Step-by-step explanation:
Multiply 1/8 by 2.5
1/8 x 2.5 = 5/16
Ryan will have completed 5/16 of his test at the 1 hour mark.
I'm always happy to help :)
Answer:
Step-by-step explanation:
Asymptotes 3
g(x) = 
Factors of denominator will be,
x² - 3x - 10 = x² - 5x + 2x - 10
= x(x - 5) + 2(x - 5)
= (x + 2)(x - 5)
Therefore, factored form of g(x) will be,
g(x) = 
Asymptotes 4
h(x) = 
= 
= 
= 
