Question

A chemical company sells a specialized industrial lubricant in 20 liter containers. A

Answer 1

The standard deviation of the sampled containers' contents is 0.36

How to determine the mean

• Data = 20.72, 20.6, 20.71, 20.92, 19.79, 20.93, 20.09, 20.27, 20.49, 20.2
• Number of data (n) = 10
• Summation of data = 20.72 + 20.6 + 20.71 + 20.92 + 19.79 + 20.93 + 20.09 + 20.27 + 20.49 + 20.2 = 204.72
• Mean (μ) =?

Mean = summation of data / number

μ = 204.72 / 10

μ = 20.472

How to determine the standard deviation

• Data = 20.72, 20.6, 20.71, 20.92, 19.79, 20.93, 20.09, 20.27, 20.49, 20.2
• Number of data (n) = 10
• Mean (μ) = 20.472
• Standard deviation (σ) =?

σ = √[[(x₁ - μ)² + (x₂ - μ)² + (x₃ - μ)² + (x₄ - μ)² + (x₅ - μ)² + (x₆ - μ)² + (x₇ - μ)² + (x₈ - μ)² + (x₉ - μ)² + (x₁₀ - μ)²] / n]

σ = √[[(20.72 - 20.472)² + (20.6 - 20.472)² + (20.71 - 20.472)² + (20.92 - 20.472)² + (19.79 - 20.472)² + (20.93 - 20.472)² + (20.09 - 20.472)² + (20.27 - 20.472)² + (20.49 - 20.472)² + (20.2 - 20.472)²] / 10]

σ = 0.36

Learn more about statistics:

brainly.com/question/8974461

#SPJ1