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vivado [14]
3 years ago
13

Which equation represents the data in this function table?

Mathematics
1 answer:
Rudiy273 years ago
3 0

Answer: The answer is B. Because 3 multiplied by x and add it by 3 equates to y. example: (x=2) 3x2+3= y. y=9 .

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Find the slope<br> 5x - 2y = 10<br><br> M=_______
Eva8 [605]

Answer:

Slope is 5/2

Step-by-step explanation:

5x-2y=10

subtract 5x from both sides

-2y=-5x+10

Then you divide -2 on both sides

y=5/2x-5

Which will result 5/2 as the slope

6 0
3 years ago
Read 2 more answers
Worth 10 points if correct answer you will get brainliest :)
barxatty [35]

Answer:

16/21

Step-by-step explanation:

5 0
3 years ago
In a newspaper, it was reported that yearly robberies in Springfield were down 25% to 78 in 2013 from 2012. How many robberies w
anastassius [24]
There were 30% in 2012 to 2013
5 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
A pile of 42 coins worth $4.90, consisting of nickels and quarters. How many nickels are there?
Ymorist [56]

Answer:14

Step-by-step explanation:

A nickel is 5 cents (20% of dollar)

and a quarter is 25 cents (25% of dollar)

We have given a pile of 42 coins worth of $4.90

Let x be the no nickels and

y be the no of quarter

therefore

x+y=42    -----1

\frac{x}{4}+\frac{y}{20}=4.90 ---2

Solving \left ( 1\right )&\left ( 2\right ) we get

x=14 & y=28

Therefore no of nickels is 14 & no of quarters is 28

6 0
3 years ago
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