Question

Jason stands in the corner of a very large field. He walks, on a bearing of 030°,

Answer 1

Answer:

Step-by-step explanation:

d + 2d = 120

3d = 120

d = 40 m

east distance was 40cos30 + 80cos120 = -5.35898 m

north distance was 40sin30 + 80sin120 = 89.282032

as 30° and 120° bearings are 90° apart, Jason needs to walk

D = √(d² + (2d)²) = d√5 or 40√5 meters or about 89.44 m to return to his original position.

we could also use √(-5.35898² + 89.282032²) = 89.44 m

direction will be

θ = arctan -89.28/5.359 = -86.565° or a bearing of 273.4°