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Liono4ka [1.6K]
2 years ago
15

Suppose a triangle has sides a, b, and c and the angle opposite the side of length a is acute what must be true?

Mathematics
1 answer:
ANTONII [103]2 years ago
4 0

The true statement about the triangle is (a) b^2 + c^2 > a^2

<h3>How to determine the true inequality?</h3>

The sides are given as:

a, b and c

The angle opposite of side length a is an acute angle

The above means that:

The side a is the longest side of the triangle.

The Pythagoras theorem states that:

a^2 = b^2 + c^2

Since the triangle is not a right triangle, and the angle opposite a is acute.

Then it means that the square of a is less than the sum of squares of other sides.

This gives

a^2 < b^2 + c^2

Rewrite as:

b^2 + c^2 > a^2

Hence, the true statement about the triangle is (a) b^2 + c^2 > a^2

Read more about triangles at:

brainly.com/question/2515964

#SPJ1

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Answer:

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Step-by-step explanation:

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The inner circle has a radius of  8 - 2 = 6 ins

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So the perimeter of the shaded region = 4 + 4/3 π + π

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scientist A dissolved 1 kg of salt in 3 litres.

scientist B dissolved 20 pounds of slat in 7 pint of water.

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