Answer:

Step-by-step explanation:
GIVEN: A farmer has
of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be
and
perimeter of rectangular pen 


area of rectangular pen 

putting value of 


to maximize 



but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen 
width of rectangular pen 
Maximum area of rectangular pen 
Hence maximum area of rectangular pen is
and dimensions are 
Answer:
AH
Step-by-step explanation:
From the figure we can see a cube ABCDEFGH.
In a cube thee are 4 interior diagonals
To find the diagonal of the cube
AH, BG, CF and DE
There are 4 interior diagonals.
The given options contain only one interior diagonal.
Therefore the correct answer is first option. AH
Answer:
1512 cm³
Step-by-step explanation:
Formula
Volume of right rectangular prism = Length × Breadth × Height
As given
Two blocks of wood are shaped as right rectangular prisms.
The smaller block has a length of 9 cm, a width of 3 cm, and a height of 7 cm.
As given
The dimensions of the larger block are double the dimensions of the smaller block.
Length of the larger block = 2 × Length of the smaller block
= 2 × 9
= 18 cm
Breadth of the larger block = 2 × Breadth of the smaller block
= 2 × 3
= 6 cm
Height of the larger block = 2 × Height of the smaller block
= 2 × 7
= 14 cm
Put in the formula
Volume of larger wooden block = 18 × 6 × 14
= 1512 cm³
Therefore the volume of the wooden block is 1512 cm³ .
Answer:
108.36 ft2
Step-by-step explanation:
Use the facts we already know and plug them into the equation.
a=12.6(8.6)
If we multiply both factors, we get 108.36.
So, the rectangle is 108.36 ft2