Ask question

Ask question

All categories

Liono4ka [1.6K]

2 years ago

8

Lila and mick have pets. lila's pet has 6.73 toy bones. mick's pet has 5 times the many toy bones lila has. how many bones does

mick's pet have?

1 answer:

vlabodo [156]2 years ago

4 0

Answer:33.65

Step-by-step explanation:

6.73 x 5= 33.65

You might be interested in

Can you guys help me with this

katen-ka-za [31]

Answer:

Step-by-step explanation:

Let the number of small boxes = x

and the number of large boxes = y

Total number of boxes = 24

Therefore, equation will be,

x + y = 24 ------ (1)

Since, volume of the smaller boxes = 9 cubic feet

And the volume of larger boxes = 24 cubic feet

Therefore, total volume of the boxes = (9x + 24y)

Since combined volume of all boxes = 441 cubic feet

Therefore, equation will be,

9x + 24y = 441 ------ (2)

4 0

3 years ago

Question 14. When solving the equation -14 = 7x + 6 what will the next stage of your working be?

mr_godi [17]

Answer:

You would subtract 6 from each side.

Step-by-step explanation:

- 14 = 7x + 6

Subtract 6 from each side:

- 14 - 6 = 7x + 6 - 6

7x = - 20

Divide each side by 7:

7x ÷ 7 = - 20 ÷ 7

x = 2 and 6/7

4 0

3 years ago

Round 12.48 to the nearest whole number

Alex Ar [27]

Answer:

13

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the odds of each of the following events. (a) an event E with Pr(E) = 4/7 (b) an event E with Pr(E) = 0.6 (a) The odds are

Dafna1 [17]

Answer:

(a) The odds of event E is 4/3.

(b) The odds of event E is 3/2.

Step-by-step explanation:

Formula for probability of an event:

$Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Formula for odds of an event:

$odds=\frac{\text{Favorable outcomes}}{\text{Unfavorable outcomes}}$

(a)

It is given that

$P(E)=\frac{4}{7}$

The probability of unfavorable event

$P(E')=1-P(E)=1-\frac{4}{7}=\frac{3}{7}$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{\frac{4}{7}}{\frac{3}{7}}$

$odds=\frac{4}{3}$

Therefore the odds of event E is 4/3.

(b)

It is given that

$P(E)=0.6$

The probability of unfavorable event

$P(E')=1-P(E)=1-0.6=0.4$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{0.6}{0.4}$

$odds=\frac{3}{2}$

Therefore the odds of event E is 3/2.

3 0

3 years ago

One-fourth of the cars that an automobile manufacturer produces are sports cars, and the rest are sedans. If one-fifth of the ca

Mashcka [7]

Answer:

Step-by-step explanation:

Let's base this on 100%, or 100 cars, which is 100% of the cars. If 1/4 of the 100 cars are sports cars, then we have

25 sports cars and

75 sedans

If 1/5 of the total cars are red, 20 of the 100 cars are red (since 1/5 is 20).

If 1/3 of the sports cars, of which we have 25, are red, then 25/3 of the sports cars are red.

Since we have 20 total red cars and 25/3 of them are sports cars, then the rest of them must be red sedans:

Total red cars - red sports cars = red sedans

$20-(\frac{1}{3}*25)$ which simplifies to

$20-\frac{25}{3}=\frac{60}{3}-\frac{25}{3}=\frac{35}{3}$

7 0

3 years ago