Ok so a) is integers
And b) is 21
Explaining for B
From 1-3 he added 2
From 3-6 he added 3
From 6-10 he added 4
From 10-15 he added 5
So we r gonna continue the sequence by adding 6
15-21 we added 6
Answer:
Step-by-step explanation:
c + f = 10 (the coach tickets + first class tickets = 10)...there is 10 people
160c + 1230f = 6950....each coach ticket is 160 and each first class ticket is 1230.....and when added, they equal 6950 (for the airfare)
c + f = 10.....c = 10 - f
160c + 1230f = 6950
sub in 10 - f for c
160(10 - f) + 1230f = 6950
distribute the 160 thru the parenthesis
1600 - 160f + 1230f = 6950
combine like terms
1600 + 1070f = 6950
subtract 1600 from both sides
1070f = 6950 - 1600
1070f = 5350
divide both sides by 1070
f = 5350/1070
f = 5 <===== she bought 5 first class tickets
c + f = 10
we found f to be 5...so sub in 5 for f and find c, the coach tickets
c + 5 = 10
c = 10 - 5
c = 5 .......and she bought 5 coach tickets
check...
160c + 1230f = 6950
160(5) + 1230(5) = 6950
800 + 6150 = 6950
6950 = 6950 (correct)....so it checks out
5 coach and 5 first class
Answer:
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) = 0.975
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
The mean number of miles between services
μ= 3408 miles
The Variance of miles between services
σ² = 249,001
σ = √249,001 = 499
Let 'X' be a random variable in a normal distribution
Given sample size 'n' =36
<u><em>Step(ii):</em></u>-
Z = -163/83.16 = 1.96
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) = P(Z≤1.96)
= 0.5 + A(1.96)
= 0.5 + 0.4750
= 0.975
<u><em>Final answer</em></u>:-
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) =0.975
Answer:
1
Step-by-step explanation:
4+x+4+x+1+x=6(2x)
3x+9=12x
3x-12x=-9
-9x=-9
9x=9
x=9÷9
=1
Answer:
if the question is 2xy²(23x²y³) then the answer is 46x³y^5
Step-by-step explanation:
