Consider the following functions. f=[(-1,1),(1,-2),(3,-4) and g=[(5,0),(-3,4),(1,1),(-4,1)} Find (f-g)(1) =
Vilka [71]
The difference between the functions give:
(f - g)(1) = f(1) - g(1) = -3
<h3>
How to find the difference between the functions?</h3>
For two functions f(x) and g(x), the difference is defined as:
(f - g)(x) = f(x) - g(x).
Then:
(f - g)(1) = f(1) - g(1)
By looking at the given tables, we know that:
f(1) = -2
g(1) = 1
Replacing that we get:
(f - g)(1) = f(1) - g(1) = -2 - 1 = -3
If you want to learn more about difference of functions:
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Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Reading a Cartesian plane
- Coordinates (x, y)
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point (3, 1)
Point (0, 3)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute in points [Slope Formula]:

- [Fraction] Subtract:

- [Fraction] Rewrite:

I have no idea I’m doing the same thing rn but good luck bro bro
Answer:
Total time taken by walking, running and cycling = 22 minutes.
Step-by-step explanation:
Let the speed of walking = x
As given,
The distance of walking = 1
Now,
As 
⇒ Time traveled by walking = 
Now,
Given that - He runs twice as fast as he walks
⇒Speed of running = 2x
Also given distance traveled by running = 1
Time traveled by running = 
Now,
Given that - he cycles one and a half times as fast as he runs.
⇒Speed of cycling =
(2x) = 3x
Also given distance traveled by cycling = 1
Time traveled by cycling = 
Now,
Total time traveled = Time traveled by walking + running + cycling
=
+
+ 
= 
If he cycled the three mile , then total time taken =
+
+
= x
Given,
He takes ten minutes longer than he would do if he cycled the three miles
⇒x + 10 = 
⇒
⇒
⇒x =
= 12
⇒x = 12
∴ we get
Total time traveled by walking + running + cycling =
min