The graph represents the heights of two climbers on a climbing wall over a 12-minute time period.
1 answer:
Both climbers rested on the wall at a constant height for 2 minutes.
<h3>How to determine the true statement?</h3>The illustrative graph that represents the climbers' movement is added as an attachment
From the attached graph, we have the following observation
- The line of Abby's movement is horizontal from x = 4 to x = 6
- The line of Brynn's movement is horizontal from x = 5 to x = 7
The difference between the endpoints of both horizontal line is
Difference = 6- 4 = 2
Difference = 7 - 5 = 2
This means that both Brynn and Abby stopped for 2 minutes
Hence, the true statement about is that (d) Both climbers rested on the wall at a constant height for 2 minutes.
Read more about graphs at:
#SPJ1
You might be interested in
Answer:
y = 9
Step-by-step explanation:
Given
4 + = 7
Isolate the term in y by subtracting 4 from both sides
= 3 ( multiply both sides by 3 )
y = 3 × 3 = 9
Answer:
The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.
Step-by-step explanation:
Let <em>X</em> = number of individuals in the United States who held multiple jobs.
The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.
The sample of employed individuals selected is of size, <em>n</em> = 225.
An individual holding multiple jobs is independent of the others.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.
But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.
Conditions of Normal approximation to Binomial are:
- np ≥ 10
- n (1 - p) ≥ 10
Check the conditions as follows:
The distribution of the proportion of individuals who hold multiple jobs is,
Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:
*Use a <em>z</em>-table.
Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.