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vaieri [72.5K]
2 years ago
10

If A+B =45 then prove thati) CotA.CotB-CotA-CotB=1​

Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0

Answer:

Step-by-step explanation:

if A+B=45\\tan(A+B)=tan(45)\\\dfrac{tanA+tanB}{1-tanA.tanB}=1\\ \implies tanA+tanB=1-tanA.tanB\\\frac{1}{cotA}+\frac{1}{cotB}=1-\frac{1}{cotA}\frac{1}{cotB}, \{tanX=\dfrac{1}{cotX} \}\\ cotA+cotB=cotA.cotB-1\\cotA.cotB-cotA-cotB=1.

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Use the image to complete the equation below
s2008m [1.1K]

Given:

A figure in which a transversal line intersect the two parallel lines.

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In the given figure, the two parallel lines are line ED and line AB, and CD is the transversal line.

Angle BPC and angle BPD lie on a straight line CD. So,

m\angle BPC+m\angle BPD=180^\circ          (Supplementary angles)

Angle APD and angle BPD lie on a straight line AB. So,

m\angle APD+m\angle BPD=180^\circ          (Supplementary angles)

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

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