Answer:
C. Point A lies on ray BC
Step-by-step explanation:
Points A and C can be connected by a segment which would be a measure of the distance between the points. Locating point B between AC, makes the three points lying on segment AC.
A ray extends from a point to infinity, a line extend to infinity on both sides, while a segment is known to have two endpoints. Therefore, points AC are the end points of the segment AC, and point B between this segment confirms that point B lies on the segment AC. Therefore, Point A lies on ray BC is not correct.
Answer:
A. $4,960
B. 8%
C. $120
Step-by-step explanation:
<u>Part A</u>
The amount in the account at the end of 3 years is the original amount ($4000) plus the earned interest ($960). That sum will be ...
$4,000 + 960 = $4,960 . . . account balance
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<u>Part B</u>
The amount of interest is computed using the formula ...
I = Prt
where I is the interest earned, P is the principal invested, r is the annual rate, and t is the number of years. Putting the given values into this equation, we can solve for r:
960 = 4000·r·3
960/12000 = r = 0.08 = 8%
The interest rate was 8%.
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<u>Part C</u>
The additional interest can be computed using the same formula as for part B.
I = Prt
I = 4000·0.01·3 = 120
The additional interest earned at a 1% higher rate would be $120.
Answer:
Step-by-step explanation:
we know that
The graph of the figure represent a vertical parabola open upward
The vertex represent a minimum
The vertex of the quadratic equation is the point (h,k)
The range of the quadratic equation is the interval for y [k,∞)
Looking at the graph
The vertex is the point (0,-6)
therefore
The range is the interval [-6,∞)
Answer:
660
Step-by-step explanation:
66 hundreds is 6600 so divided by 10 it's 660
Answer:
The fraction of the students who failed to went partying = 
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students
⇒ No. of students partied before the exam = 
× 100
⇒ No. of students partied before the exam = 20
No. of students who not partied before the exam = 
Thus the fraction of the students who failed to went partying = 
