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2 years ago

If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at

Mathematics

1 answer:

elixir [45]2 years ago

7 0

The vertex U' is located at (-4, -5)

<h3>How to determine the location of U'?</h3>

The vertices are given as:

U = (-4, 5)

V = (-6, 2)

The rule of transformation is given as:

Reflection across the x-axis

This is represented as:

(x, y) => (x, -y)

So, we have:

U' = (-4, -5)

Hence, the vertex U' is located at (-4, -5)

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Can someone please help me with this question? I don't know how? What is the volume of a rectangular prism with a length of 2x –

lesantik [10]

Volume is legnth times widht times height
lenght=2x-1
width=x-2
height=x+1
multiply all together
use mass distributive property
distributive=a(b+c)=ab+ac so extending that
(a+c)(c+c)=(a+b)(c)+(a+b)(d) then keep distributing so
(2x-1)(x-2)(x+1)
do each one seperately
do the first two first and put the other one (x+1) to the side for later
(2x-1)(x-2)=(2x-1)(x)+(2x-1)(-2)=(2x^2-x)+(-4x+2)=2x^2-5x+2
then do the other one
(x+1)(2x^2-5x+2)=(x)(2x^2-5x+2)+(1)(2x^2-5x+2)=(2x^3-5x^2+2x)+(2x^2-5x+2)=2x^3-3x^2-3x+2

the lasst form is 2x^3-3x^2-3x+2

3 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Please answer this question asap

lukranit [14]

Answer:

Use the formula

P(X,y) ___y=x__(Reflection)_____P'(y,x)

I think it will help you.

8 0

2 years ago

Polly bought a bag of s sour candies. She ate 74 of the candies. Write an expression that shows how many sour candies Polly has

swat32

Answer:

s-74

Step-by-step explanation:

She ate 74 candies, out of the total S candies. So, if we do S-74, well find how many are left.

4 0

3 years ago

Sylvie folds a large piece of paper in half. The fold divides the paper into two equal parts. She folds it in half again. When s

Nikolay [14]

Each time you fold a paper it will double the amount of parts. When you think about it, it's just multiplying by 2 a bunch of times.

One fold is 2 times 1, which is 2.
The second fold is 2 times 2, which is 4.
The third fold is 4 times 2, which is 8.

Using this process, we can simplify that into exponents. If the amount of times you fold is x and the parts double for each fold, then the amount of parts can be represented by:

$2^{x}$

So if the amount of parts is given and we need the amount of folds, just keep doubling until you get to 64. The amount of times you doubled is the number of times Sylvie folded.

Later you will learn that the opposite of an exponent is a logarithm, which would look like this:

$log_{2}(64) = ?$

But don't worry about that yet.

6 0

3 years ago