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Ainat [17]
2 years ago
11

Again with this please​

Mathematics
1 answer:
ElenaW [278]2 years ago
5 0

Answer:

a) A dozen= 24

3 dozen= 24 x 3

= 72

b) 1 dozen= 12 bananas

A dozen cost= 24

So, 1 banana cost= 24/12

= 2

So, 6 bananas would be 2 x 6 = 12

c) 1 dozen= 12 bananas

A dozen cost= 24

1 banana cost= 24/12

= 2

d) I need to know how many people are there in your class so please mention that first :)

Mark me brainliest pleaseee

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lukranit [14]

Answer:

846,838,805

Step-by-step explanation:

Add 846837947+858

3 0
2 years ago
How do u correct the graph? ​
konstantin123 [22]

Answer: In my opinion you could just shorten the number of orders so that it's not so long.

Explanation: The numbers can be from every 20 orders so 900, 920, 940...so on.

5 0
3 years ago
TRI has vertices T(-3, 4), R(3, 4), and I(0,0). Is TRI scalene, isosceles, or equilateral?
KatRina [158]

Answer:

Isosceles

Step-by-step explanation:

Graph your triangle!

Then, do the distance formula. So from T to I is 5 units, R to I is 5 units, and T to R is 6 units. As two side lengths are congruent, the triangle is isosceles.

Hope this helps!


4 0
3 years ago
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
Please assist me with the following compound interest problems.​
Sphinxa [80]

Answer:

  see the attachments below

Step-by-step explanation:

When the calculations are repetitive using the same formula, it is convenient to put the formula into a spreadsheet and let it do the calculations.

That is what was done for the spreadsheet below. The formula used is the one given in the problem statement.

__

For doubling time, the formula used is the one shown in the formula bar in the attachment. (For problem 11, the quarterly value was used instead of the monthly value.) It makes use of the growth factor for the period used for the rest of the problem.

The doubling time is in years.

__

The doubling time can also be found using a graphing calculator. In the second attachment, we have written a function that shows the multiplier for a given interest rate r and compounding n. The x-intercept in each case is the solution for t that makes the multiplier be 2. The steeper curve is associated with the higher interest rate.

8 0
3 years ago
Read 2 more answers
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