if ABCD and EFGH are similar, then you should be able to line up corresponding points (for example, A corresponds to E, B corresponds to F). if they're different sizes, you should then dilate one of them so that they are the exact same size.
I don’t think there is anything wrong with the coming there is just a 50% chance that It would land on tails and there’s a 50% chance that it will land on heads ♀️☺️
Answer:
y = 0.5cos(4(x+π/2)) -2
Step-by-step explanation:
The centerline of the oscillation is at -2, so only the 2nd and 4th choices are viable.
The multiplier of x is computed from (2π)/period. One period is π/2, so the multiplier of x is ...
... 2π/(π/2) = 4 . . . . . matching the 2nd selection.
The horizontal offset in the second equation (π/2) is of no consequence, as it is one full period of the function.
The peak-to-peak amplitude of the oscillation is 1 unit, so the multiplier of the cosine function (which usually has a peak-to-peak value of 2 units) is 0.5. Every offered answer has that characteristic.
The appropriate choice is the 2nd one:
... y = 0.5cos(4(x+π/2)) -2
Answer:
The answer is √5 .
Step-by-step explanation:
You have to rationalize the fraction in order to get rid of surd in the denorminator by multiplying √3 to both numerator amd denorminator :
Answer:
1. AA
2. SSS
3. I´m not sure about this one, I´m sorry
4. Not similar
Step-by-step explanation:
This photo can help you identify!! I hope this helps
