Month 6, work down below
months / students
0 30 45
1 36 48
2 42 51
3 45 54
4 51 57
5 57 60
6 63 63
9514 1404 393
Answer:
Jesse
Step-by-step explanation:
Jesse's distance in 60 seconds would be ...
(60 s)(15 m)/(6 s) = 150 m
Peyton's distance in 60 seconds would be ...
(60 s)(22 m)/(10 s) = 132 m
Jesse travels farther in the same amount of time, so Jesse is moving faster.
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You might find it simpler just to compute the rate of each.
Jesse: (15 m)/(6 s) = 2.5 m/s
Peyton: (22 m)/(10 s) = 2.2 m/s
Jesse's speed is higher.
If the width is w then the length = 2w + 40, so the area
= w(2w + 40)
= 2w^2 + 40 w
I think it should be 7g?
Not sure tho
