The answer is f the question I’d 800times
Answer:
The 1st Blank is: A pure substance, or simply a substance
The 2nd blank on the left is: Elements
The 3rd blank on the right is: Compounds
The 4th blank which is the second middle one is: A mixture
The 5th blank which is the bottom left one is: Heterogeneous mixture
The 6th blank which is the last one on the bottom right is: Homogeneous mixture
Look at the step-by-step explanation if you get confused at the bottom.
Step-by-step explanation:
The 1st Blank: I would just put a pure substance.
The 2nd blank on the left: They are three characteristics of elements but just put elements.
The 3rd blank on the right: They are three characteristics of compounds but just put compounds.
The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.
The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.
The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
B dhs.3200
because 10% of 4000=400
20%=800
4000-800=3200
Answer:
-> a + c = 1250 ____________ (1)
-> 8a + 5c = 7300 __________(2)
There were 900 children and 350 adults.
Step-by-step explanation:
Let the number of children at the carnival be c.
Let the number of adults at the carnival be a.
The admission fee at a carnival is $5 for children and $8 for adults on Friday.
1250 people attended the carnival and $7300 was collected. This means two things:
-> a + c = 1250 ____________ (1)
-> 8a + 5c = 7300 __________(2)
We now have a system of equations representing the problem.
To solve, make a subject of formula in (1):
a = 1250 - c _______(3)
Put (3) in (2):
8(1250 - c) + 5c = 7300
10000 - 8c + 5c = 7300
10000 - 7300 = 3c
3c = 2700
c = 2700 / 3 = 900
Put the value of c back in (3):
a = 1250 - 900 = 350
Therefore, there were 900 children and 350 adults at the carnival.
