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3 years ago

9/2 divided by 1/4= ? in simplest form

Mathematics

1 answer:

Allisa [31]3 years ago

7 0

Answer: 18

Do Keep Change Flip (KCF)

Keep: 9/2

Change: ÷ into ×

Flip: 1/4 into 4/1

Your new problem should be 9/2×4/1

Multiply

9/2×4/1=36/2

36/2=18

Final Answer: 18

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HELP DUE IN AN HOUR

miss Akunina [59]

Answer:

D) no solution.

Step-by-step explanation:

4(x + 1) ≤ 4x + 3

First, distribute 4 to all terms within the parenthesis:

4(x + 1) = 4(x) + 4(1) = 4x + 4

4x + 4 ≤ 4x + 3

Isolate the variable, x. Treat the "≤" as an equal sign, what you do to one side, you do to the other. Subtract 4x and 4 from both sides:

4x (-4x) + 4 (-4) ≤ 4x (-4x) + 3 (-4)

4x - 4x ≤ 3 - 4

0 ≤ -1

Since x was eliminated from the inequality, and you need the x for the inequality, your answer is D) no solution.

4 0

3 years ago

Read 2 more answers

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

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