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Black_prince [1.1K]
3 years ago
9

Joe is playing a game with a regular die. If the number that turns up is even, he will gain 5 times the number that comes up. If

it is odd, he will lose 10 times the number that comes up. He tosses a 3. Express the results as an integer.
Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

30 dollars

Step-by-step explanation:

The question states that if an even number comes up then Joe will win 5 times of the number that shows up for example, if 2 comes up he will win 5×2 dollars i.e., 10 dollars. If an odd number shows up he will lose 10 times the number which i.e. if 1 shows up he will lose 1×10 = 10 dollars

It says in the question that Joe tosses a 3 which is an odd number so he will lose 10 times of 3

So he will lose 10×3 = 30 dollars.

Doss [256]3 years ago
4 0

Answer:

If Joe tosses a 3, he will lose 30 dollars.

Step-by-step explanation:

To express this in a general form we can use functions which will be expressed in terms of the number tossed.

  • We know that if the number that turns up is <u>even,</u> he will gain 5 times the number.
  • Therefore, the function for when the number x is even would  be <u>f(x) = 5x </u>

  • On the other hand, if the number is <u>odd,</u> he will lose 10 times the number.
  • Therefore, the function for when the number x is odd will be f(x) = -10x

Finally Joe tosses a 3, 3 is an odd number, therefore the function we will use will be f(x) = - 10x

f(3) = -10(3) = -30

Therefore, Joe will lose 30 dollars.

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a simple test is the following

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so

even function
subsitute -x for each and see if we get the same function
remember to fully expand these

g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one

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