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Finger [1]
2 years ago
13

(5+4) +10=5+(4+10) A. True B. False

Mathematics
2 answers:
eduard2 years ago
7 0
True as they both add up to 19
Studentka2010 [4]2 years ago
3 0

Answer:

A. True

Step-by-step explanation:

One of the ways to check this is solving each side of the equation.

(5+4)+10=5+(4+10)

Remember PEMDAS.

Parenthesis first.

(9)+10=5+(14)

Now, you can drop the parenthesis and add the numbers together.

9+10=19

5+14=19

19=19

This is a true statement.

Hope this helps!

If not, I am sorry.

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What is the correct answer?
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5 0
3 years ago
@jdoe<br><br> As promised. The link will be whatever.
Lady_Fox [76]
Ok, so we see in
y=a(x-h)^2+k
vertex is (h,k)
vertex is highest or lowest point
on one side, it goes up and other side it goes down

if a is positive, then it goes down then up
if a is negative, it goes up then down

we see
f(x)=2(x+3)^2+2
2 is positive
goes down then up
vertex is (-3,2)

so decreases from -infinity to -3 or ininterval
(-infinity,-3)

answer is first option
6 0
3 years ago
Melissa mows many lawns in her neighborhood. She mows lawns for $95 per lawn. She also offers full landscape maintenence for $12
olga55 [171]

9.52

125 * 4 = 500

500 * 9.52 = 4,760

6 0
3 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0
2 years ago
If 5/8ths is equal to $531.25 what is the remaining portion of the number.
Nimfa-mama [501]
5/8 = .625
531.25 / .625 = 850
850 - 531.25 = $318.75

7 0
3 years ago
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