Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=
for x²-4x+16=0
x=
x=
x=
x=
x=
x=
the roots are
x=-4 and 2+2i√3 and 2-2i√3
Answer:
Step-by-step explanation:
m = slope where
m = rise / run
rise = y2 - y1
run = x2 - x1
where
the given point P1 = (7, -12)
and is in the form of (x1,y1)
and
the given point P2 = (-9,36)
is in the form of (x2,y2)
then
m = ( y2 - y1 ) / ( x2 - x1 )
m = ( 36 - (-12) ) / ( -9 -7 )
m = ( 36 + 12 ) / ( - 16 )
m = 48 / - 16
m = - 3
the slope is negative 3
slope = - 3
Answer:
3+2x
Step-by-step explanation:
Distribute the equation out.
1/4(12+8x)
(1/4*12)+(1/4*8x)
Multiple those out to get a new equation
3+2x
You cannot add those together because of the variable. Theres no way of knowing what x equals so this is as far as you can go therefor making the answer 3+2x
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = 
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
(a) minor arc: arc VX
major arc: arc VYX
(b) 248 degrees
(c) Tangent: UV
Secant: UY
Step-by-step explanation:
(b) 360 - 112 = 248
(c) UV crosses on the circumference of the circle at exactly one point
UY crosses through the circle at exactly two points
