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Nady [450]
2 years ago
10

Margaret makes bracelets and sells them to tourists. the function s(t) approximates how many bracelets margaret makes per hour.

the function w(h) represents how hours per week margaret spends making bracelets. what are the units of measurement for the composite function s(w(h))?
Mathematics
1 answer:
Fantom [35]2 years ago
4 0

The units for the composite function s(w(h)) is <u>bracelets over a week</u> when the function s(t) approximates how many bangles Margaret makes per hour and the function w(h) represents how many hours per week Margaret spends making the bracelets.

To define the unit of the composite function s(w(h)), we first need to find the units of the functions s(t) and w(h).

The function s(t)  represents the number of bangles per hour, so its unit will be bangles over an hour.

The function w(h) represents the hours per week spent on making the bracelets, so its unit will be hours over a week.

Now, we can define the unit of the composite function s(w(h)).

To find the unit of the composite function we follow these steps:-

s(w(h)),

= s(hours over a week) {replacing the function w(h) by its units},

= (bangles over an hour(hours over a week)) {replacing the function s(t) with its units},

= bangles over a week {Simplifying}.

Thus, the units for the composite function s(w(h)) is <u>bracelets over a week</u> when the function s(t) approximates how many bangles Margaret makes per hour and the function w(h) represents how many hours per week Margaret spends making the bracelets.

Learn more about the units of a composite function at

brainly.com/question/15056566

#SPJ4

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3 years ago
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Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

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