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ad-work [718]
3 years ago
5

If h(x)=4x^2-16 we’re shifted 7 units to the right and 3 units down what would the new equation be

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

4(x-7)^2 - 19

Step-by-step explanation:

Shifting 7 units to the right:  4(x-7)^2 - 16.

3 units down:                         4(x-7)^2 - 16 - 3, or    4(x-7)^2 - 19

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ANSWER PLEASSSSSSSSSSSE
kolezko [41]

Answer:

The answer is A hope this helps

Step-by-step explanation:

3x^2+14x+16=0

(3x+8)(x+2)=0

x=-8/3 or -2

7 0
3 years ago
Please help me I need help
ozzi
D. is your answer
4/x^2

hope it helps
7 0
3 years ago
Read 2 more answers
Solve the following absolute value equation.<br><br> −8 − 2 |5X – 17| = −14
Levart [38]

If 5x - 17 ≥ 0, then |5x - 17| = 5x - 17 and the equation reduces to

-8 - 2 (5x - 17) = -14

-8 - 10x + 34 = -14

-10x = -40

x = 4

If 5x - 17 < 0, then |5x - 17| = -(5x - 17) = -5x + 17 and we have

-8 - 2 (-5x + 17) = -14

-8 + 10x - 34 = -14

10x = 28

x = 2.8

4 0
2 years ago
Which fraction is<br> equivalent to 1/8
Law Incorporation [45]
The equivalent fractions are 2/16 8/64
6 0
2 years ago
Read 2 more answers
Please Help me I really need it :)
lapo4ka [179]

Answer:

C

Step-by-step explanation:

For the given intervals

( - ∞, - 5) ← use any value < - 5 but not - 5, the parenthesis ) indicates that x is less than - 5 but not equal to - 5

(- 5, - 1) ← - 4, - 3, - 2 can be used but not - 5 or - 1

(- 1, 4) ← 0, 1, 2, 3 can be used but not - 1 or 4

(4, ∞ ) ← use any value > 4 but not 4

Hence

3 can be used in (- 1, 4)

- 6 can be used in (- ∞, - 5)

zero can be used in (- 1, 4)

- 5 cannot be used in any of the given intervals

5 0
3 years ago
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