Answer:
A. can trace a particular file in a few seconds.
Step-by-step explanation:
The new locator has now easy access and user friendly. The data saved here is useful when you are locating a file. It will take few seconds to locate a file. This saves time in finding the relevant files. The new locator is user friendly and is not really technical to operate it.
Use PEMDAS
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)

Answer:
$2500 at 8%.
$2900 st 5%.
Step-by-step explanation:
Let x be the amount invested at rate of 8% and y be the amount invested at the rate of 5%.
We have been given that Heather has divided $5400 between two investments. We can represent this information as:
The return on her investment is $345.
Earnings from the investment at 8% will be 8% of x.
Earnings from the investment at 5% will be 5% of y.


We will use substitution method to solve our system of equations. From equation (1) we will get,
Substituting this value in equation (2) we will get,




Therefore, Heather has invested an amount of $2900 at 5%.
Let us substitute y=2900 in equation (1) to solve for x.



Therefore, Heather has invested an amount of $2500 at 8%.
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Answer:
d. does not exist
Step-by-step explanation:
The given limits are;
,
and 
We want to find

By the properties of limits, we have;

This gives us;

Division by zero is not possible. Therefore the limit does not exist.