How to graph y = 2|x + 3| - 4
1 answer:
The x-intercepts and the y-intercepts of the function is that determines the graph is:
- x-intercepts = (-5,0) and (-1,0)
- y-intercepts = (0,2)
The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.
From the given equation:
y = 2|x+3| - 4
To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.
By doing so, the x-intercepts and the y-intercepts of the function is:
- x-intercepts = (-5,0) and (-1,0)
- y-intercepts = (0,2)
Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.
Learn more about determining the graph of an absolute equation here:
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Answer: p = 0.9337
Step-by-step explanation: from the question, we have that
total number of pen (n)= 15
number of pen that has never been used=9
number of pen that has been used = 15 - 9 =6
number of pen choosing on monday = 3
total number of pen choosing on tuesday=3
note that the total number of pen is constant (15) since he returned the pen back .
probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
probability of picking a pen that has been used on tuesday = 6/15 = 2/5
probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5
on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .
we know that
probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.
to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution
p(x=r) =
n= total number of pens=15
r = number of pen chosen on tuesday = 3
p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
by slotting in the parameters, we have that
p(x=3) =
p(x=3) = 455 *
p(x=3) = 455 * 0.064 * 0.002176
p(x=3) = 0.0633
thus probability that 3 of the pens has been used on tuesday. = 0.0633
probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337