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Oduvanchick [21]
2 years ago
10

Megan runs at an average rate of 12 minutes per mile. How many miles will she run in an hour?

Mathematics
1 answer:
Shtirlitz [24]2 years ago
4 0
The answer is 5 miles. Megan can run for an hour. 1 hour divided by 12 gives 60/12 in minutes (1 hr is 60 minutes).
60/12 is 30/6 is 15/3 is 5 miles.
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Sonja [21]

Answer:

6/16, which can be reduced to 3/8

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3 years ago
Stephen evaluated (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). His work is shown below
Maksim231197 [3]

Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated (6.34\times 10^{-7})(4.5\times 10^3).  His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - (6.34\times 10^{-7})(4.5\times 10^3)

Step 2 - (6.34\times 4.5)(10^{-7}\times 10^3)

Step 3 - (28.53)(10^{-4})

Step 4 - 28.53\times 10^{4}

Error is the step as 4 sign is negative.

So correct step is 28.53\times 10^{-4}

Step 5 - 28.53\times 10^{3}

Error is the step as there is 4 in place of 3.

So correct step is 28.53\times 10^{-4}

The step 4 and 5 describe the errors Stephen made.

7 0
3 years ago
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A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground.
Aneli [31]
Answer : 59.04 is the angle 
8 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

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3 years ago
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Aleonysh [2.5K]

Answer:

bro no one cares

Step-by-step explanation:

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2 years ago
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