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Oduvanchick [21]
2 years ago
10

Megan runs at an average rate of 12 minutes per mile. How many miles will she run in an hour?

Mathematics
1 answer:
Shtirlitz [24]2 years ago
4 0
The answer is 5 miles. Megan can run for an hour. 1 hour divided by 12 gives 60/12 in minutes (1 hr is 60 minutes).
60/12 is 30/6 is 15/3 is 5 miles.
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4, 9, 13, 18,<br> The common difference 'd' is
Ivanshal [37]

Answer:

There is no common difference

Step-by-step explanation:

     4      9      13      18

diff     5      4       5

Because the difference between 9 and 13 is 4

and the difference in the other terms is 5

there is no common differeence

7 0
2 years ago
Esteban is reading a book with 16 pages. He has read 9 pages so far. How many pages does Esteban have left to read? Write two eq
Zielflug [23.3K]

Answer:

7 pages

Step-by-step explanation:

Given the total number of pages in the book are 16

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Therefore There are 7 pages left out to be read.

8 0
3 years ago
What is 5/8 times 4? Then simplify your answer.
scZoUnD [109]

The answer is 2 1/2. Because you need to cross cancel then you take the "freeway", and you get 5/2 and simplified is 2 1/2.And since half equals .5 it would be 2.5 just in case you also needed decimal.

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4 0
3 years ago
Read 2 more answers
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

8 0
2 years ago
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