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2 years ago

Find the midpoint of points A(10,-7) and B(6, 1) graphically.

Mathematics

1 answer:

sashaice [31]2 years ago

4 0

Answer:

(8,-3)

Step-by-step explanation:

Midpoint Formula: $(\frac{x^{1}+x^{2} }{2}, \frac{y^{1} +y^{2} }{{2} } )$

Plug in your numbers from the coordinates:

(10+6/2, -7+1/2)

(16/2, -6/2)

(8,-3)

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challenge- you have 500- foot roll of chain link and a large field. you want to fence in a rectangular playground area. What are

Lynna [10]

the largest you can have without going over 500 feet is 22.71 in length and 22 in width.

22.71*22=499.62ft

the leftover fence is 0.38ft

hopes this helps

6 0

3 years ago

The length of a table is 8 times longer then it’s width. If the perimeter is 72, how wide is the table?

Andrews [41]

Answer:

4 units wide

Step-by-step explanation:

Let the width of the table be 'w'

Given:

Perimeter of the table is, $P=72$

The perimeter of the rectangular table is given as the sum of all the sides of the rectangle. The sides include two lengths and two widths.

Length of the table is 8 times longer than its width. Therefore,

$Length,L=8w$

Now, perimeter is given as:

$P=2L +2w\\P=2(8w)+2w\\P=16w+2w\\P=18w\\w=\frac{P}{18}$

Now, plug in 72 for 'P' and solve for 'w'. This gives,

$w=\frac{P}{18}\\\\w=\frac{72}{18}\\\\w=4$

So, the table is 4 units wide.

6 0

4 years ago

3 4 5 6

stellarik [79]

C, if you show a picture maybe I can answer it correctly

3 0

3 years ago

Read 2 more answers

Prove that sin^4x + cos^4x= sinxcosx

yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

$sin^4(x) + cos^4(x)$

We can rewrite this as:

$(sin^2(x))^2 + (cos^2(x))^2$

Now we can add and subtract cos^2(x)*sin^2(x) to get:

$(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)$

We can complete squares to get:

$(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2$

and we know that:

cos^2(x) + sin^2(x) = 1

then:

$1 - 2*sin(x)^2*cos(x)^2$

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

$1 - \frac{sin^2(2*x)}{2}$

Then the simplification is:

$cos^4(x) + sin^4(x) = 1 - \frac{sin^2(2*x)}{2}$

7 0

3 years ago

WILL MARK BRAINLIEST 4. Find x. A) 10 B) 10.5 C) 11 D) 11.5

Galina-37 [17]

10.5 ( near parallel to the one next to x which will equal 11 or 11.5 but 10.5 is associated with its compression.

Answer = 10.5

(thanks if you give branliest it is always appreciated)

7 0

3 years ago