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Step2247 [10]
3 years ago
9

If there's 15 players total 1/3 are wearing red shoes 2/5 or wearing blue shoes and everyone else is wearing black shoes what is

the fraction of people with black shoes
Mathematics
1 answer:
Volgvan3 years ago
6 0

Answer:

\frac{4}{15} is the fraction of people wearing with black shoes.

Step-by-step explanation:

Given:

If there's 15 players total, 1/3 are wearing red shoes, 2/5 are wearing blue shoes and everyone else is wearing black shoes.

Now, to find the fraction of people with black shoes.

Total players = 15.

Fraction of people wearing red shoes = \frac{1}{3}.

So, number of people are wearing red shoes:

\frac{1}{3} \times 15\\\\=5.

Fraction of people wearing blue shoes = \frac{2}{5} .

Thus, number of people wearing blue shoes:

\frac{2}{5} \times 15\\\\=6.

And rest are wearing black shoes.

Now, to get the number of people wearing black shoes by subtracting number of people are wearing red shoes and blue shoes from the total number of players:

15-5-6\\\\=15-11\\\\=4.

Thus, the fraction of people wearing black shoes:

\frac{Number\ of\ people\ wearing\ black\ shoes}{Total\ number\ of\ players}

= \frac{4}{15} .

Therefore, \frac{4}{15} is the fraction of people wearing with black shoes.

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Step-by-step explanation:

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3 years ago
translate into an algebraic expression and simplify if possible. what number exceeds m by five more than n
Kisachek [45]

Answer:

If the number is x, then the equation is;

x-m = 5 + n

Step-by-step explanation:

Here, we want to write the given statement in algebraic form

What number exceeds m by five more than n

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3 years ago
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

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3 years ago
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denpristay [2]
39 because you have to subtract six 6 times so 6*6=36 so 75-36=39
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3 years ago
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Which statements about geometric sequences are true?
finlep [7]

Answer:

Geometric sequences have a common ratio between terms.  TRUE

Geometric sequences are restricted to the domain of natural numbers.  FALSE

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Step-by-step explanation:

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