You need to prove that <A = <E
since c is the midpoint of line AE then AC = EC
i dont remember the name of the theroem that states that when a triangle has two sides and an angle in common that it is congruent i think it called SAS congruence therom. use that to prove that the <| s are congruent then use CPCTC to prove that <A = <E. then prove that they are || by usint the int angle therom.
Two ratios that are equivalent to 3:11 are 6:22 and 9:33 :)
Answer/Step-by-step explanation:
Part A:
Evidence 1: the line passes through the point of origin, (0, 0)
Evidence 2: it has a unit rate or constant of proportionality, k = y/x = 5/3
Part B:
When extended, if the ray passes through the point, (18, 30), then y/x of this point, should give us the same unit rate (k) of 5/3 of the graph.
Thus:
y/x = 30/18
Simplify
= 5/3
Thus, it has the same unit rate of the graph, therefore, the ray passes through the point (18, 30).
Answer:
c=9
Step-by-step explanation:
Answer: you will win for any distances greater than 190ft.
To find the rate, you’ll first need to find the slope between two points
Slope formula: m=y^2 - y^1 / x^2 - x^1
Plug the equation in: 76-38/4-2
Substitute. subtract, & divide and you get m=19
Then you have to do slop intercept form:
Formula: y-y1= m(x-x1)
Plug in the equation:
Y-38=19(x-2) substitute
Y-38=19-38 distribute
Y= 19x
Then you graph it (I attached a graph pic)
On the graph there’s two lines that intersect at (10,190). For x less than 10, you will run farther than your friends = you will win.