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2 years ago

Can someone help me out on this problem and show work

Mathematics

1 answer:

DochEvi [55]2 years ago

6 0

Answer: 4230.14

Step-by-step explanation:

The amount that the balance is multiplied by each month is

$\frac{2448}{2040}=1.2$ .

So, after t months, the balance is $1700(1.2)^{t-1}$ .

Substituting in t=6, we get the balance is

$1700(1.2)^{6-1}=\boxed{4230.14}$ , to the nearest hundredth.

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Step-by-step explanation:

Given that:

the sample proportion p = 0.39

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The sampling distribution from the sample proportion is approximately normal.

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(b)

Here;

the sample proportion = 0.39

the sample size n = 400

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Thus, using normal approximation.

From the sample proportion, the sampling distribution is approximate to the mean $\mu_{\hat p} = p = 0.39$

the standard deviation $\sigma_{\hat p} = \sqrt{\dfrac{p(1-p)}{n} }$

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The test statistics can be computed as:

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$Z = \dfrac{0.3 - 0.39 }{0.0244}$

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