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sladkih [1.3K]
3 years ago
15

I NEED HELP WITH THIS QUESTION!!

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

- 1

Step-by-step explanation:

The product of the slopes of lines perpendicular to each other is - 1

Given y = 4x - 5 with slope 4

y = - \frac{1}{4} x - 5 with slope - \frac{1}{4} then

4 × - \frac{1}{4} = - 1 proving the lines are perpendicular

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the ratio of strawberry to banana batter is 2:3 we need 30 cups of batter total what percent of the cake is banana
motikmotik

60 percent.  I hope this was help for you

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3 years ago
Evaluate 1 3 m − 1 − 1 2 n 3 1 ​ m−1− 2 1 ​ nstart fraction, 1, divided by, 3, end fraction, m, minus, 1, minus, start fraction,
luda_lava [24]

Answer:

  0

Step-by-step explanation:

Apparently, you want the value of ...

  \dfrac{1}{3}m-1-\dfrac{1}{2}n = \dfrac{m}{3}-\dfrac{n}{2}-1\\\\=\dfrac{21}{3}-\dfrac{12}{2}-1=7-6-1\\\\=\boxed{0}

The value of the given expression for the given variable values is zero.

3 0
3 years ago
Go step by step to reduce the radical. <br> The square root of 96
lakkis [162]

Answer:

Step-by-step explanation:

We want to reduce the radical. In order to do that, we want to find the factors of 96 that are square numbers

The factors of 96 are:

1, 96, 2, 48, 3, 32, 4, 24, 6, 16...

16 is a square number, so we can rewrite

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5 0
2 years ago
At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are fi
VARVARA [1.3K]
The two answers are the one selected and the choice |x-5| ≤ 1. The steps to solve the other equation are:
|x-5| ≤ 1
x-5 ≤ 1, x-5 ≥ 0
-(x-5) ≤ 6, x-5 is less than 0
x ≤ 6, x ≥ 5
x ≥ 4, x is less than 5
x ∈ [5,6]
x ∈ [4,5]
4 ≤ x ≤ 6
(^which was the original answer^)

7 0
3 years ago
Use lagrange multipliers to find the maximum volume of a rectangular box that is inscribed in a sphere of radius r
vesna_86 [32]

For the derivative tests method, assume that the sphere is centered at the origin, and consider the circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined

1

by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner by

x2+y2+z2=r2 =⇒z= r2−(x2+y2). Then the volume of a box with this coordinate for the corner is given by

V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),

and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the boundary of this domain, so we need only consider critical points contained inside the domain in order to carry this optimization out.

For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint x2 + y2 + z2 = r2<span>. </span>

7 0
3 years ago
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