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irina1246 [14]
2 years ago
7

Find the length of the missing side. Leave your answer in simplest radical form.

Mathematics
1 answer:
lana66690 [7]2 years ago
7 0

Answer:

\sqrt{69}

Step-by-step explanation:

from the pythagorean theorem:

a^2 + b^2 = c^2\\10^2 + b^2 = 13^2\\100 + b^2 = 169\\b^2 = 69\\b = \sqrt{69}

You might be interested in
You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as
Lesechka [4]

The correct question is;

You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as a fraction or percent. If necessary round your answer to the nearest hundredth. Find the probability of spinning an odd number, flipping heads, then spinning another odd number? Write your answer as a fraction in simplest form.

Answer:

If the spinner has an even number of spaces, the probability of spinning an odd number, flipping heads, then spinning a yellow is = 1/8

Whereas, if the spinner has an odd number of spaces, more information is needed

Step-by-step explanation:

The answer will depend on whether the spinner has an odd or even number of spaces.

Now, if we suppose that the spinner has an even amount of numbers on it, there will be an equal number of odd and even numbers.

Thus the probability of spinning an odd number is ½.

Also, the probability of flipping heads on a coin is ½.

Thus, the probability of spinning an odd number, flipping heads, then spinning another odd number is;

= ½ × ½ × ½ = ⅛

Similarly,

If the spinner has an odd amount of numbers on it, the probability of spinning an odd number will vary. For instance, if there are 5 spaces on the spinner, the probability of spinning an odd number will be

3

However, if there are 9 spaces, the probability will be 5/9

So,we can conclude that;

If the spinner has an even number of spaces, the probability of spinning an odd number, flipping heads, then spinning a yellow is = 1/8

Whereas, if the spinner has an odd number of spaces, more information is needed.

6 0
2 years ago
Please help meeeeee thanksss
Alex

Answer:

Step-by-step explanation:

it's 3     hmmm it tells you rise over run.. just about where they are asking for the answer.. what do you not get about the question?  

3 0
3 years ago
Can someone help me with this
dedylja [7]
The is 20 characters long
4 0
3 years ago
Number 6,8, and 10. ​
Aliun [14]

I think number 10 is 4/9

6 0
2 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
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