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lawyer [7]
4 years ago
9

Two kids are liars, three can only say the truth. Jane: " Julia is only a liar, if John is telling the truth." Julia: "If Joey d

oesn’t lie, then either Jane or John do." Joey: " Jack lies, as does Jane or Julia." John: "If Julia is telling the truth, then Jane or Joey do as well." Jack: "If you round up Jane, Joey and John, you will have at least one liar." The compulsive liars are_____
Mathematics
2 answers:
alexira [117]4 years ago
4 0
The compulsive liars are Jane and Jack. From the statement above, lying to them is nothing. They don't feel any guilt or conscience in doing it. Compulsive liars are those people who lies all the time or making lies are their habit. They find comfort in doing it and does not care of the consequences.
Alina [70]4 years ago
4 0

Answer:

Julia and Jack

Step-by-step explanation:

The statement says Jack lies as an absolute and when jack speaks he says "if you round up Jane, Joey, and John one is a liar" which implies none of them are liars.

And that gives you the three people who tell the truth and leaves Jack and Julia as the liars.

You can reason it by taking a statement that certainly said one person is lying or telling the truth and you can check to see if it makes sense with the rest assuming they are telling the truth.

We can start with Joey (who said Jack was a liar). That means we know one liar and somebody is telling the truth. Lets look at Jack's statement and can conclude that Jane and John also weren't liars (since that would've made him truthful).

Now I know one liar and 3 that are speaking the truth. That leaves Julia as the second compulsive liar.

Therefore, Jack and Julia are the compulsive liars.

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If n = 4, all of the following expressions are equivalent except
Lorico [155]

Answer:

n to the power of -2

Step-by-step explanation:

i counted all the others and this is the only one that doesn't add up to 16. the last answer is -16 not 16 so there you go.

8 0
3 years ago
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
rodikova [14]

First isolate the "y" in the equation.

2y - x = -12 Add x on both sides

2y - x + x = -12 + x

2y = -12 + x   Divide 2 on both sides to get "y" by itself

y = \frac{-12 +x}{2}

y = -6 + \frac{x}{2}

Your slope is \frac{1}{2}.

For the equation of the line to be parallel to the given equation, the slopes have to be the same. So the parallel line's slope is also \frac{1}{2}

y = mx + b

y = \frac{1}{2}x + b

To find "b", you plug in the point (18,2) into the equation

y = \frac{1}{2}x + b

2 = \frac{1}{2}(18) + b

2 = 9 + b Subtract 9 on both sides

2 - 9 = 9 - 9 + b

-7 = b


Your equation is:

y =\frac{1}{2}x - 7

8 0
3 years ago
Re-write 12% as a common fraction in a simple form​
Liula [17]

Answer:

\frac{3}{25}

Step-by-step explanation:

 

          12 \% = \frac{12}{100} = \frac{3}{25}

3 0
3 years ago
Read 2 more answers
There were 4983 students going on the field trip. Each bus could hold 60 students. How many buses did they need to transport all
goblinko [34]

Answer:

eighty four 84 84 84 84 84

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3 years ago
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Which steps can be used to solve for the value of y ?<br> (y + 57) = 178
avanturin [10]
You have to subtract 57 from 178 and you will get your answer.
y= 121
6 0
4 years ago
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