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2 years ago

Help me solve this pls ?

Mathematics

1 answer:

UNO [17]2 years ago

3 0

Answer:

x = 2

Step-by-step explanation:

divide both sides by 2

then simplify

Apply exponent rule and vowla theirs your final answer of x = 2

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natta225 [31]

Answer: it would be (2, -4) because if you flip it it will still be the same just at a different angle.

Step-by-step explanation:

8 0

3 years ago

Explain how to divide negative and positive rational numbers.

I am Lyosha [343]

Answer:

The rule for multiplying and dividing rational numbers

Ok so if both numbers are negative or positive the answer will be positive. but if one number is positive and the other is negative the answer is negative.

Hope this helps

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7 0

3 years ago

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive dress = ?

Solution:

Let

The number of cheaper dresses be x

The number of expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250

$x \times90 +y \times 140 = 5250$ = $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress = 20 + number of expensive dress

x = 20 + y---------------------------------------(1)

$(20+y) \times90 +y \times 140 = 5250 = 5250$

$(20 \times 90 +y\times 90) +y \times 140= 5250$

$1800 + 90y+ 140y = 5250$

$1800 + 230y = 5250$

$230y =5250 -1800$

$230y = 3450$

$y = \frac{3450}{230}$

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0

4 years ago

Solve for s.<br> 0.5s +1= 7+ 4.58<br> S =?

Lana71 [14]

Answer:

s = 21.16

Step-by-step explanation:

0.5s +1= 7+ 4.58

Combine like terms

0.5s +1=11.58

Subtract 1 from each side

0.5s +1-1= 11.58-1

.5s = 10.58

Multiply by 2

.5s *2 = 10.58*2

s = 21.16

4 0

3 years ago

Read 2 more answers

Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago