The hardcover version of a book weighs twice as much as it's paperback version. The hardcover book and the paperback together we
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The fraction of a defective item getting by both inspectors is =
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 = .
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = .
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) = ×
=
=
= 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
Answer:
- <u><em>The height of the missing rectangle is 0.15</em></u>
Explanation:
The image attached has the mentioned <em>histogram</em>.
Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.
Only the rectangle for the class [3,4] is missing.
The height of each rectangle is the relative frequency of the corresponding class.
The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.
In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.
<u>1. Sum of the known relative frequencies</u>:
- 0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85
<u>2. Missing frequency</u>:
- 1 - 0.85 = 0.15
<u>3. Conclusion</u>:
- The height of the missing rectangle is 0.15
